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/sci/ - Science & Math


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15111209 No.15111209 [Reply] [Original]

IT LITERALLY SAYS 0.9999999... HOW CAN IT BE 1? Prove it robustly without a bunch of algebra handwaving

>> No.15111211

>>15111209
What is the definition of this thing as a real number?

>> No.15111216

>>15111209
So? It doesn't have to look like 1.000 to be equal to 1.000

>> No.15111226

>>15111209
2/2 also literally says 2/2. It's still 1 though.

>> No.15111230

>>15111209
wikipedia is a good starting point

>> No.15111235

>>15111209
>IT LITERALLY SAYS 1+1 HOW CAN IT BE 2?

>> No.15111238

>>15111211
>>15111216
>>15111226
>>15111230
>>15111235
>No robust arguments

>> No.15111243

>>15111238
>can't be bothered by reading any of the proof that's already there. . .

>> No.15111246

>>15111243
its not proof its algebra handwaving and bogus walmart logic

>> No.15111249

>>15111209
It follows from the assumption that if some number x satisfies x ≤ 1/n for all natural numbers n, then x ≤ 0.
>how do you know that?
You don't. It's an assumption.

>> No.15111254
File: 8 KB, 205x246, 1664875776204329.jpg [View same] [iqdb] [saucenao] [google]
15111254

>>15111209
>So? It doesn't have to look like 1.000 to be equal to 1.000

>> No.15111276

>>15111209
could you give me a real number between 0.999... and 1 ? here is your proof

>> No.15111277

>>15111249
okay i'll just assume that 0.99999... =/= 1 instead then

>> No.15111279

>>15111276
0.9999... and put and another nine at the end of it

>> No.15111283

>>15111277
Then you have to accept that there are numbers that are larger than 0 but smaller than every 1/n.

>> No.15111285

>>15111283
yes ill just assume that

>> No.15111290

>>15111279
this is supposed to be an infinite sequence yet I admit its abusive notation

>> No.15111291

>>15111285
good

>> No.15111315

1/3 = 0.333333333…. right?

And 0.3333333… + 0.333333… + 0.33333… equals 0.9999999….

But 1/3 + 1/3 + 1/3 equals….

>> No.15111321

>>15111315
>1/3 = 0.333333333…. right?
Prove it.

>> No.15111322

>>15111315
0.33333... is irrational
>why?
By assumption

>> No.15111330

>>15111209
>HOW CAN IT BE
9/inf=0

>> No.15111341

>>15111315
>1/3 = 0.333333333…. right?
no

>> No.15111342

>>15111321
1/3 = 3/10 + 1/30
= 0.3 + 1/30
= 0.33 + 1/300
= 0.333 + 1/3000
:
= 0.3... + 1/inf
= 0.3... + 0
= 0.3...

>> No.15111350

>>15111342
infinities not a number, you can't divide by it.
you can only take the limit of that fraction as the denominator approaches an arbitrarily large number. But, the limit is never the same as the actual value.
There exists no number such that n times 0 = 1
so there would be no number you divide 1 by to get 0.

>> No.15111357

>>15111209
for every rational number less than 1, 0.999… is strictly greater than it. and since 0.999… is obviously not greater than 1, and since the rational numbers are dense, we can conclude that 0.999… must be equal to 1. questions?

>> No.15111358

>>15111350
>infinities not a number, you can't divide by it.
sure you can, and more:
1/inf = 0
0/inf = 0
1 + inf = inf
1 - inf = -inf
inf + inf = inf
inf/inf undefined
inf - inf undefined
1^inf undefined

you can't do everything with inf as with a number, doesn't mean you can do nothing tho

>> No.15111372

>>15111342
>= 0.333 + 1/3000
>...
>= 0.3... + 1/inf
I like how you conveninetly marked the nonsequitur as with those dots.

>> No.15111374

>>15111358
it isn't even a number, its a concept. all that stuff you wrote is just wrong.

>> No.15111379

The reals are dense; between any two non-equal reals are more reals.

Therefore, if 2 reals DO NOT have any reals between them, they must be equal.

>> No.15111380

>>15111374
You're a big gay and you should have let me handle it instead of jumping in. His mistake is a lot more basic and a lot less up for debate than what you think it is.

>> No.15111383

>>15111379
so any two consecutive reals are equal?
using this logic, any real consecutive to a real consecutive to another real would also be equal.
Then, this continuing endless would mean all reals are equal to each other.

>> No.15111388

>>15111383
no two reals can be “consecutive” since theres always one in between.

>> No.15111389

>>15111209
>HOW CAN IT BE 1?
its a trivial proof left as an exercise to the reader

>> No.15111402

>>15111209
Proof by Dedekind cut:

Assume to contradiction that x is a rational number such that

0.999... < x < 1

0.999... is greater than any finite string of 9s so for any natural number n

1-1/10^n < 0.999... < x < 1

1-x < 1/10^n

10^n < 1/(1-x)

n < log(1/(1-x))

Let n = ceiling(log(1/(1-x)))+1

ceiling(log(1/(1-x)))+1 < log(1/(1-x))

This is a contradiction, so x does not exist and 0.999... = 1.

>> No.15111415
File: 178 KB, 779x778, 1648642699510.jpg [View same] [iqdb] [saucenao] [google]
15111415

>>15111380
i don't want to be a big gay

>> No.15111421

>>15111380
bro wtf
apologize

>> No.15111422

>>15111402
now prove it using cauchy sequences

>> No.15111423

>>15111422
Via Cauchy sequences:

0.999... = (0.9, 0.99, 0.999,...) = lim as n-> inf of 1-1/10^n = 1

>> No.15111426

The difference is infinitesimal.
If you have an object that measures 0.999 cm and your ruler has a 0.001 cm precision on the measurement, you won't be able to tell 0.999 and 1.000 apart.
This is the same but at the mathematical level.

>> No.15111427

>>15111209
0.9999... = x
9.9999... = 10x
9 = 9x
x = 1
1 = x = 0.9999...

>> No.15111431

>>15111426
Excruciatingly retarded post.

>> No.15111436

>>15111427
You're being dishonest.
0.9999 = x
9.9990 = 10x
9.9990 - 0.9999 = 9x
8.9991 = 9x
x = 8.9991/9
x = 0.9999

This is true for any number of 9s.

>> No.15111438

>>15111427
how did you get from the second line to the third

>> No.15111442
File: 47 KB, 645x729, 8d6.jpg [View same] [iqdb] [saucenao] [google]
15111442

>>15111436
>you're being dishonest because your argument is correct

>> No.15111444

>>15111438
Subtract x=0.999... from both sides.

>> No.15111450

>>15111444
you'd get 9.00....1x on the right then

>> No.15111454

>>15111450
No, 10x-x = 9x. Need to go back to kindergarten?

>> No.15111461

>>15111454
you took away .9999... not 1. you can't assume they are equal and use it to prove they are equal

>> No.15111462

>>15111442
In mathematical notation, because 0.999... is not rigorous.
[math] 0.999... = \lim \sum_{k=1}^{n}\frac{9}{10^k} [/math]

>> No.15111465

>>15111461
>you took away .9999... not 1
Not me, but yes, that's what he did. 9.999... - 0.999... = 9. 10x -x = 9x

>you can't assume they are equal
Where was this assumed? x was subtracted, not 1. Need to go back to kindergarten?

>> No.15111469

>>15111462
It's rigorous, and your objection that his argument results in true statements like 0.9999 = 0.9999 is nonsensical.

>> No.15111475

>>15111374
W-A agrees with >>15111358

>> No.15111477

>>15111469
He's making a valid point and you're the retard. 0.9999... = x is a nonsensical statement until you define what the infinite sum it alludes to sums up to, which is what you have to prove in the first place.

>> No.15111491

>>15111477
>He's making a valid point and you're the retard. 0.9999... = x is a nonsensical statement until you define what the infinite sum it alludes to sums up to
No, that's not how math works. That's as silly as saying you need to define the exact value of x before solving x^2-2x+1 = 0. And that has nothing to do with his initial objection, which is proof enough that he's retarded, since he thinks the same argument making correct conclusions about finite strings of 9s invalidates it.

>> No.15111501

>>15111477
It's not a sum, it's a Fedekind cut or Cauchy sequence. Retard.

>> No.15111505

>>15111465
sorry, you are right. but the real problem with his proof is that he put .999... x 10 = 9.999... which isn't true.

>> No.15111508

>>15111505
It is by definition of base 10. Multiplication by the base moves the decimal one place to the right.

>> No.15111510

>>15111374
>all that stuff you wrote is just wrong.
prove it

>> No.15111511

>>15111491
That's as silly as saying you need to define the exact value of x before solving x^2-2x+1 = 0.
No, you imbecile. If anything, it's like saying you need to define what the values of the symbo;s '1' and '0' are.

>>15111501
Take your actual meds.

>> No.15111512

>>15111462
.999... doesn't equal the limit of that sum.

>> No.15111515

>>15111512
>source: my ass

>> No.15111519

>>15111508
yes. thanks to base 10 we know that if a number is multiplied by then, and moves one place to the right, the now empty space is a 0, not a 9.
.999... x10 = .999...90

>> No.15111520

>>15111511
>If anything, it's like saying you need to define what the values of the symbo;s '1' and '0' are.
Yes, which is equally retarded, since we already know what they mean.

>Take your actual meds.
LOL, you lost.

>> No.15111521

>>15111520
>we already know what they mean
Literal subhuman level of intellect.

>> No.15111523

>>15111515
>you need a source for a definition

>> No.15111525

>>15111519
>the now empty space is a 0
What empty space? Moving the decimal doesn't create new digits, it simply shifts them. There is no 0, only 9s.

>> No.15111526

>>15111521
I agree, if you don't know what 0 and 1 refer to then you have literal subhuman level of intellect.

>> No.15111533

>>15111526
They don't refer to anything until they're defined, subhuman. Thanks for going out of your way to demonstrate your mental deficiency.

>> No.15111538

>>15111533
They are defined, you would already know the definitions if you weren't a subhuman.

>> No.15111552

>>15111538
>They are defined
I didn't say they weren't. Every time you post, you demonstrate the necessity of eugenics. The worthless animal you call your mother should have been sterilized.

>> No.15111566

>>15111525
.999... is a placeholder for a decimal expansion with an arbitrarily large natural number of digits.
all natural numbers are finite. so no matter what arbitrarily large natural number is chosen, it will be finite. so, once the decimal expansion has reached this arbitrarily large number of digits, it would stop. there would be no more 9s to the right. multiplying it by 10 would then change the digit in the place of place in the decimal expansion of the final 9 to a 0, reducing the number of 9s to the right of the decimal point by 1, and increasing the number to the left of it by 1. therefore, its not the same number as .999... + 9, since that would have 1 more 9 digit than .999... x10 would.
all natural numbers are finite. that is the core of the argument.

>> No.15111583

>>15111436
Just because something is true for any number of numbers doesn't mean it is true with an infinitie number of numbers.
Imagine you have an infinite number of balls with a natural number written on it which you put into a box. The rules are that you put balls into the box in order of their label, and when you get a number which is a perfect square (eg 4), you take out the number which is its square root (eg 2). For an infinite number of turns, the box will be empty as every number has a square. However, for any number of turns, the box will be nonzero since evry turn either adds a ball (when it is not a perfect square) or keeps the same number of balls (exchanges a square root for its perfect square)

>> No.15111589

1/9 = 0.111...
+
8/9 = 0.888...
=
9/9 = 0.999...

>> No.15111593

>>15111552
>I didn't say they weren't
Then your objection "They don't refer to anything until they're defined" is meaningless, subhuman.

>> No.15111595

>>15111589
>1/9 = 0.111...
>8/9 = 0.888...
post proof

>> No.15111596

>>15111566
>.999... is a placeholder for a decimal expansion with an arbitrarily large natural number of digits.
No.

>> No.15111598

>>15111566
> an arbitrarily large natural number of digits.
Why are you moving the goal post by cherry picking natural numbers? Why not just an endless sequence?

>> No.15111603

>>15111593
LOL. Post again to demonstrate just how mentally deficient you are.

>> No.15111606

>>15111598
>he thinks he can have a non-natural number of digits
go on then, show me a number with 1.5 digits.

>> No.15111607

>>15111603
Not an argument. Thanks for admitting you're subhuman.

>> No.15111608

>>15111512
It's the definition based on decimal notation.

>>15111491
Facts and logic vs "No you're wrong"

>>15111583
Because the calculation is impossible for an infinite number there has to be another way of proving it.
There might be one but the way he did is based on unrigorous math and trying to redefine what it means to add and multiply numbers, when you mess up something learned in grade school the result you're lucky to get the right result.
If you do the same math replacing 0.999.. with the limit you won't get 1, because even though the difference between the two numbers gets closer to zero it never truly equals 0.
Or to put it simply 0.999... will never be a natural number, it will always be a real number with infinitesimal distance from the real/natural number "1".

>> No.15111609

>>15111566
>.999... is a placeholder for a decimal expansion with an arbitrarily large natural number of digits.
what makes you say that?

>> No.15111611

>>15111607
0.999... stands for the infinite sum 9/10+9/100+... which is defined as the limit of the sequence of the partial sums. In other words, it's 1 by definition. With this definition, your algebraic manipulation is a pointless tautology. Without this definition, it's meaningless nonsense. OP and others like him are questioning the definition. They don't see why an infinite sum should have any specific value since in their minds "it never gets there".

>> No.15111613

>>15111608
>It's the definition based on decimal notation.
limits aren't part of the basis of decimal notation.

>> No.15111614

>>15111606
an endless sequence doesn't have a 1.5th element either. I see no problem here.

>> No.15111615

>>15111595
post disproof

>> No.15111617

>>15111609
sequences can only have a natural number of terms. and you can have sequences with an arbitrarily large number of terms. and all natural numbers are finite. those three things together are the basis for the argument.
i hope that answers your question well enough anon.

>> No.15111619

>>15111613
Because decimal notation is used to represent fixed-length number.

>> No.15111623

>>15111614
it also has a natural number of terms.
if you are working with a set of non-finite numbers beyond natural numbers and supposing that they exist, and can be used just as natural numbers can in certain situations, then that would be a different, new sort of decimal expansion. but its not the same one as the normal one. it would be an expansion of the natural numbers. one which is unobservable, non-measurable, and undetectable in the real world.

>> No.15111627
File: 115 KB, 600x474, 1673294584160.jpg [View same] [iqdb] [saucenao] [google]
15111627

>>15111617
>sequences can only have a natural number of terms.

>> No.15111628

>>15111623
>it also has a natural number of terms.
meant any sequence should have a natural number of terms.

>> No.15111630

>>15111627
post a sequence with a non-natural number of terms, like 1.5 terms or 1/2 a term then.

>> No.15111632

>>15111630
an infinite sequence

>> No.15111633

>>15111632
there's only finite sequences

>> No.15111640

>>15111617
0.999... is not a sequence though

>> No.15111644

>>15111238
I didn’t give an argument, I asked, how are you defining 0.999… ?

>> No.15111647

>>15111608
>Facts and logic vs "No you're wrong"
Agreed, "0.999... doesn't make sense" is not an argument.

>> No.15111648

>>15111640
the digits can be arranged in a sequence.
9 in the 1/10ths place
9 in the 1/100ths place
and so on

>> No.15111656

>>15111611
>0.999... stands for the infinite sum 9/10+9/100+...
No, it's a real number which are constructed as Cauchy sequences or Dedekind cuts, not infinite sums. You don't need to do any infinite sums to prove 0.999... = 1. See >>15111402

>> No.15111672

>>15111633
Proof?

>> No.15111689

>>15111672
its just my opinion.

>> No.15111693

>>15111283
Infinitesimal

>> No.15111707

>>15111647
Define the [math] ... [/math] operator then.

>> No.15111743

>>15111707
It means "and so forth"

>> No.15111746

>>15111689
Your opinion doesn't matter in math.

>> No.15111751

>>15111209
you see, this is actually what is Christ vs. God. Jesus is.9... God, is 1. they are both separate entities, but are equivalent. The divine mystery. Jesus will always have another 9 to complete our placeholder in the interdimensional universe, as his nines never end, but God is already whole, he is 1.

>> No.15111754

>>15111648
0.999... is not a placeholder for a sequence

>> No.15111755

>>15111746
saying infinite sequences do exist is also a opinion though anon.

>> No.15111760

>>15111751
Seems like we have a visitor from /his/

>> No.15111765

>>15111755
None of this shit exists. You assume something to be true and see where it leads. If It turns out those assumptions were useful you use them again.

>> No.15111769

>0.111... = 1/9
>0.222... = 2/9
>0.333... = 3/9
>0.444... = 4/9
And so on. Continue the pattern and you have:
>0.999... = 9/9
>9/9 = 1

>> No.15111770

>division by zero
NOOOOO you cant do that!! With that you can prove that 1=2 which it obviously isnt!!
>infinitesimals
WAOWERZ this is so useful! with this i can prove that 0.999... = 1, which obviously is true!

>> No.15111784

>>15111755
No, it's really demonstrable. The sequence of natural numbers is infinite.

>> No.15111785

>>15111770
Where were infinitesimal used for this proof? >>15111402

>> No.15111790

>>15111785
Do you know the definition of dedekind cuts? Pick up a book in real analysis, i recommend Rudin's principles of mathematical analysis.

>> No.15111793
File: 88 KB, 1024x512, FOffBWwaUAA0Z5j.jpg [View same] [iqdb] [saucenao] [google]
15111793

>>15111790
Damn bro you just memorize definitions with no understanding

>> No.15111817

0.999... isn't equal to 1 because 0.999... doesn't exist.

>> No.15111822 [DELETED] 

>>15111770
>division by zero...you can't do that!!!
>division by infinity? that's A-okay!

>> No.15111823
File: 7 KB, 233x216, b96bcd77d412a4aaeadb8d0f39ae8661.jpg [View same] [iqdb] [saucenao] [google]
15111823

>>15111817
But what if it did tho

>> No.15111825
File: 473 KB, 704x659, 19684064823.png [View same] [iqdb] [saucenao] [google]
15111825

>>15111793
You dont seem to understand dedekind cuts or infinitesimals so you're clearly out of your depth

>> No.15111832

>>15111790
I do, what don't you understand about my proof?

>> No.15111839

>>15111832
>spoon-feed me
Read your "proof" again and then read real analysis again, not everything is going to be handed to you on a silver platter in life

>> No.15111842

>>15111817
But algorithms exist, and you can write an algorithm to give a rational approximation to within any desired precision

>> No.15111845

this thread is basically a philosophy of mathematics thread.
don't think these problems will be ironed out any time soon.

>> No.15111851

>>15111845
This is a grade school equality

>> No.15111864

1-0.9=0.1
1-0.99=0.11
1-0.999=0.111
...
1-0.999999999... = 0.1111111111..... which clearly isnt zero. Sometimes i wonder if all of you are just a bunch of seventh graders

>> No.15111866

>>15111839
OK, so there is nothing wrong with the proof and you're just whining. Thanks for admitting that.

>> No.15111884

they are only represented differently

>> No.15111885

>>15111864
1-1=0
1-1.0=0
1-1.00= 0

>> No.15111908

>>15111866
I accept your concession

>> No.15111920

>>15111864
>1-0.999999999... = 0.1111111111.....
No it doesn't
[math]1-0.9=0.1[/math]
[math]0.1-0.09=0.01[/math]
[math]1-0.999...=0.000...[/math]

>> No.15111941

>>15111851
do you happen to think grade school maths is rigourous

>> No.15111996

>>15111908
Of what? You're the one who stopped arguing.

>> No.15111999

>>15111941
You're right, 1+1=2 is unrigorous.

>> No.15112004

>>15111999
yeah, you'd need to read principia mathematica for it to be rigorous.

>> No.15112008

>>15111209
>without algebra

im gonna do it brah


let's say a=0.999999999999999999.....

10*a=9.9999999999999....
so 10*a-9=0.999999999999999999.....
which means 10*a-9=a
so we get 10*a-a=9
9*a=9
a=1

>> No.15112011

>>15111920
i think you didn't even pass high-school
at least for now
am i wrong ?

>> No.15112012

>>15111743
Define it in terms of operations on numbers.
And so forth could mean the 9s end at some point because in the case of any real world measurement that's what would happen.

>> No.15112016

>>15111864
>1-0.9999...=0.1111..

The fuck you are dumb
Does in your shithole country exist something named "calculator" ? Use it and see

>> No.15112026

>>15111647
if 0.9999... is a number which makes sense according to you then i dare you to add it to 3 and write the result

you won't be able to write it so the number itself doesn't make sense because it's not a number it's a representation of the infinitesimal difference applied to 1

>> No.15112033

keep adding 9's forever and eventually it just becomes 1, simple as.

>> No.15112040

>>15112033
You can't reach forever. That's why there's limits

>> No.15112041

>>15111279
You can't put another 9 at the end of it, the "..." means it goes on forever.

>> No.15112050
File: 65 KB, 540x959, NINTCHDBPICT000706430807.jpg [View same] [iqdb] [saucenao] [google]
15112050

>>15111864
1% of 1 is eleven hundredths

>> No.15112056

>>15112041
Yes, so it's any number between 0.9 and 0.999...
Doesn't matter how many 9-s you put there, it's still not 1

>> No.15112061

>>15112056
Again, it goes on forever. No matter how far you went you'd find more 9s. You're not putting on any particular number of 9s.

>> No.15112065

>>15111276
Yes actually.
0.999... + 0.000...

>> No.15112080 [DELETED] 

>>15112011
>am i wrong ?
Yes. I am actually a professor of mathematics at Cambridge.

>> No.15112093

>>15112056
Name a number between 0.999… and 1

>> No.15112113

>>15112061
It's an infinite set of finite numbers

>> No.15112129

>>15112113
It's a single number, whose written form continues infinitely.

>> No.15112132

>>15111342
I love how he blew their arguments out of the water and they’re left seething in shambles

>> No.15112149

>>15111209
>Prove 0.99... = 1.
>and DON'T use mathematics. Give me a real answer.

>> No.15112155

>>15111209
Floating point is fake and gay.
QED.

>> No.15112164

>>15112129
So it's any number with any amount of 9-s in it, ergo an infinite set of numbers

>> No.15112173

>>15112164
No, it's the number in which the 9s go on forever. As in, if you look at the nth digit, for any value of n however large, it will be 9.

>> No.15112178
File: 306 KB, 1128x480, 15fea505-1e96-42fb-be44-131804fb13b3_screenshot.png [View same] [iqdb] [saucenao] [google]
15112178

>>15111209
>why isn't it bigger than one
>it just isn't
>why not, you stupid bastard

>> No.15112187
File: 223 KB, 1292x682, The Outer Limits of Reason - The outer limits of reason what science mathematics and logic cannot tell us .png [View same] [iqdb] [saucenao] [google]
15112187

>>15111209
>HOW CAN IT BE 1?
It can't be. As stated in pic related.

>> No.15112192

>>15112026
3.9999...

>> No.15112228

>>15112041
Oh?

So what is pi then? 3.1415159265... ? 3.1415...? 3.14...? 3....? ... ?

>> No.15112233

>>15112093
0.999 + nigger where nigger is the half the difference between 1 and 0.999...

>> No.15112241

>>15112187
limit cultists won't like this one

>> No.15112246

>>15112228
What kind of question is that? It's irrational.

>> No.15112252

>>15112173
Yes, so it's an infinite set of numbers

>> No.15112259

>>15112252
It is a particular number, or rather a particular representation of a number, which contains an infinite number of digits.

>> No.15112265

>>15111209
>it literally says "arbor" how can that BE "tree"

>> No.15112273

>>15112259
So it can be any number with any amount of digits that falls within that infinite set of numbers

>> No.15112275
File: 3.41 MB, 2052x1184, tom Campbell computing reality.png [View same] [iqdb] [saucenao] [google]
15112275

>>15112241
True. People that believe in physical countinuousness won't like it either. The physical world is discrete/digital (computable/informational).

>> No.15112284

>>15112273
No. It is not 0 with a million 9s, or a billion 9s, or a googolplex 9s, but 0 with an infinite number of nines.

>> No.15112289

>>15112284
So any amount of 9s, got it

>> No.15112293

>>15112289
No, "infinity" and "any amount" are not the same. 0.9999... is the number with the property that no matter what digit of it you look at, it will always be a 9.

>> No.15112301
File: 134 KB, 496x496, 1595871990984.jpg [View same] [iqdb] [saucenao] [google]
15112301

>>15112293
>0.9999... is the number with the property that no matter what digit of it you look at, it will always be a 9.
But there's a 0 in it, you're not very good at math, are you?

>> No.15112325

>>15111372
each line is exactly =1/3
it's your job to show where it suddenly starts diverging from that

>> No.15112328

friendly reminder that you may not assume that 1/3 = 0.999.... since 0.99.... is irrational

>> No.15112330

>>15112301
You know what I mean. Any digit after the decimal point.

>> No.15112333

>>15112330
Still doesn't make you any less wrong

>> No.15112336

>>15112333
You are either a troll or stupid and I'm not sure why I'm still responding to you.

>> No.15112341

>>15112328
>t. friendly idiot
not one but TWO mistakes, lol

>> No.15112342

>>15112336
>I'm not sure why I'm still responding to you.
Because you can't accept that you are wrong

>> No.15112349

>>15112341
ad hominem

>> No.15112371

>>15112349
nah, that would be argumenting just based on your idiocy.
i'm criticizing you based on fitting two mistakes in a short sentence.
the rest is just being impolite, not AH

>> No.15112393

>>15112065
In terms of limits
[math] \lim \sum_{k=1}^{n} \frac{9}{10^k} + \lim \frac{1}{10^{n+1}} [/math]

>> No.15112462

>>15112393
>In terms of limits

>> No.15112479

0.9... is a recursive function with zero computational time. If it had a small amount of computational time it would never reach 1. But since it is computed instantly you can simply say that it doesn't equal 1.

>> No.15112573

>>15112012
>Define it in terms of operations on numbers.
Why? It's not an operation.

>And so forth could mean the 9s end at some point
No.

>because in the case of any real world measurement
Irrelevant.

>> No.15112598
File: 111 KB, 953x613, wNQjUVS.jpg [View same] [iqdb] [saucenao] [google]
15112598

>>15111209
OP is retarded.

Here we go again...

>> No.15112605

1/3 = 0.333... 1/3
2/3 = 0.666... 4/6
3/3 = 0.999... 9/9

>> No.15112607

>>15112012
>could mean the 9s end at some point

No. They *categorically* go on forever.
When you run the math, 0.999.. is, -precisely- 1.

>> No.15112707
File: 1.46 MB, 498x379, 1670795969087208.gif [View same] [iqdb] [saucenao] [google]
15112707

>>15112598
>1=0.999...

>> No.15112859

>>15111209
It's not 1. It clearly shows that it's not.

>> No.15112861

>>15112598
Retarded proofs for retarded poster. Good job.

>> No.15112863

>>15112598
I'm not sure why he claimed infinitely small numbers don't exist. Abraham Robinson created a rigorous framework for infinitesimals.

>> No.15113076

>>15111277
Then if we call your assumption x, what is the difference between 1 and x, ie what is the value of 1-x?

>> No.15113331

>>15112598
>circle arguments
yawn

>> No.15113350
File: 28 KB, 600x600, 1671885974674360.jpg [View same] [iqdb] [saucenao] [google]
15113350

0.075 proves 1 isn't the lowest unit. There is '~' which symbolizes a logical quart.

0.99999 does equal 1 but it's a retard error in base system.

>> No.15113460

>>15111315
1/3 is not equal to 0.333333333...
Under the base 10 system, dividing 10^x by 3 gives you an infinitely recurring decimal. It's impossible to represent 1/3 as a decimal number. You must use fractions.

>> No.15113466

It's not 1
It's always a hair width away from 1
But the limit of it approaches to 1

>> No.15113471

>>15113460
That's what the "..." means- infinitely recurring decimal.

>> No.15113475

>>15111209
> 1/3 = 0.33333...
> 3 * 1/3 = 3 * 0.33333...
> 3/3 = 0.99999...
Since 3/3 = 1,
1 = 0.99999...

No algebra

>> No.15113480

>>15113475
That's literally algebra

>> No.15113485

>>15111442
You're being retarded. Don't you know what happens when you multiply 999999 by 9? You can't just slap an extra 9 onto the end. This is grade school math, dipshit.

>> No.15113490

>>15111321
> Step 1: 1/3, how many times does 3 fit in 1? Zero
> What's left over? One.
> Alright, since we still have stuff left let's move on
> Step 2: 10/3, how many times does 3 fit in 10? Three!
> What is the extra? One.
> Alright, since we have stuff left let's move on.

Repeat step 2 forever.
Each step is one decimal.
So 0.333... repeating 3s infinite times.

>> No.15113494

>>15113490
so that means there's always a remainder.
so it would be .333... and a non-zero remainder based on how many 3s you calculated to.

>> No.15113495

>>15113471
1/3 cannot be written as a decimal. You can only get infinitesimally close to the value of 1/3. Simple as.

>> No.15113496

x = 0.99999......9
1-x = 0.00000...1 = dx
dx is so small with infinite zeroes that it literally becomes zero

>> No.15113497

>>15113495
Yes, it's infinitely recurring so you can't write it out in full, that's what the "..." means.

>> No.15113500

>>15111519
Infinity can be a tough concept to grasp

There is no empty space, only nines. All the way down.

>> No.15113501

>>15113496
>dx is 0
that will simplify my integral calculations a bit

>> No.15113506

>>15111623
How many halfwaypoints does your hands have to pass to clap together?

Do they ever reach each other?

>> No.15113509

>>15111633
What is the biggest number?

>> No.15113511

>>15113485
>Don't you know what happens when you multiply 999999 by 9?
Where is that in the argument? Retard.

>> No.15113516

>>15112008
That's a nice proof
I like this proof

>> No.15113519

>>15112026
4

>> No.15113522

>>15111209
>1-0.999... = ?
>0.999... - 1 = ?
I know none of you midwits will answer.

>> No.15113526

>>15113522
they are infinitesimals

>> No.15113530

>>15113522
>>1-0.999... = ?
>>0.999... - 1 = ?
...1 and ...-1
next

>> No.15113533
File: 533 KB, 2434x1512, universe creation bwhit .png [View same] [iqdb] [saucenao] [google]
15113533

>>15112598
You can't put exactly 1/3 water in each glass to an infinite amount of decimal places. This is an idealistic, non -physical procedure. Matter is quantized and so there would not be the same amount in each. There would be a positive natural number for each minimal finite element. There are no infinite anything in the physical world. No infinite divisibility, no continuousness, no analyticity. None of that. see here
>>15112275
This is why everything blows up when you try and go below the planck length by the way. It's a processor overload. It's pixelated down there.
You confuse the math model with the physical reality. These continuous math models have utility because the planck length, for instance, is so small that the models make useful predictions down to a non--arbitrary resolution and limited decimal places. There is a minimal delta t of time as well, see pic.
And none of this infinite/continuous/analytic stuff could ever be verified either using measurements upon the experiential/sensual datastream, ie it could not be confirmed empirically. This is a metaphysical claim. I am fine with this myself, being that I am an idealist and platonist and not an empiricist, and I don't believe that the physical world is fundamental, but derivative, so this infinite/continuous/analytic stuff could be grounded in mind, the all mind, god, platonic realm, whatever you want to call it, but it's not physical.

>> No.15113537
File: 163 KB, 1612x578, bwhitworthquantreal pix cycles.png [View same] [iqdb] [saucenao] [google]
15113537

>>15112598
Wrong pic related here
>>15113533
should be pic related

>> No.15113539

>>15113533
Yes in reality there is no infinites

But we're discussing math. Not reality aren't we?

>> No.15113548

>>15113539
Universe is infinitely long and small

>> No.15113553

>>15113548
We don't know that
Just a decent guess

>> No.15113600

>>15113539
I think you should start by defining 'reality'. A discussion about what 'is' or what is 'real' is a meta physical (ontological) discussion, not a scientific/empirical one. I myself do not think the (effectively) objective (I say effectively because of recent verifications of wigner's friend type thought experiments) datastream called the physical world is the only reality. I don't believe that a physicalist metaphysical viewpoint can account for things like consciousness, identity over time, the invariant across space and time nature of number, and all kinds of other universals. So I don't believe that math is necessarily fake or not 'real' just because it is not physical. My main point for posting that post was from a position of PHYSICAL finitism. On Mathematical finitism I will admit to being agnostic at this point. This is why I like these threads. I look at the subject matter open mind. This is why I watch the shit out of Norman J. Wildberger vids as well. such as this
https://www.youtube.com/watch?v=fCZ8jJCVinU
He is, of course, a physical AND math finitist or ultra-finitist or maybe even a double mega omni finitist. He definitely is an empiricist with regard to math, but I don't think he realizes that this in itself is a metaphysical (ontological) position, and so it in itself can not be verified by the scientific method or the subjective sensual datastream that gets somehow beamed into our mind to experience, that we call the 'objective' physical world. He was pushed back a bit about this in this interview.
https://www.youtube.com/watch?v=l7LvgvunVCM
I don't know the time stamp but it is there somewhere.

>> No.15113613

>220 posts about 0.999...
did I timeslip back into 2014

>> No.15113627

>>15113600
You use too many flowery words to describe sollipsism.

Math is useful. It has practical purpose.
Reality is real enough, wether infinite or not.

Things are never perfect, or 100%
Just good enough.
Close enough to 1 to be 1 for all purposes.

>> No.15113658

>>15113627
>You use too many flowery words to describe sollipsism
This is not really an argument against anything I said. Sounds like you are approaching an argument from and appeal to consequence. See pic. I am not asserting that metaphysical solipsism is true. I didn't even mention solipsism. Epistemic solipsism, though, is just a brute fact that any world view has to deal with. Do you have access to someone ELSE'S sensual datastream of the physical world? I don't.
>Math is useful. It has practical purpose.
Yes
>Reality is real enough, wether infinite or not
You still didn't define 'reality'. Certainly the physical data stream that our mind is presented with is real enough to achieve the VR concepts of immersion and presence. More immersive that the dream datastream in terms of being more persistent.

>> No.15113661
File: 56 KB, 1285x214, appeal to consequence .png [View same] [iqdb] [saucenao] [google]
15113661

>>15113627
Forgot pic
here
>>15113658
see pic

>> No.15113684
File: 3 KB, 305x165, download.png [View same] [iqdb] [saucenao] [google]
15113684

>>15111209
ok. Assuming your graphic description is an infinite amount of zeros, one can define this as being the sum in picrel.
the sum of (q)^n with n going to infinity for a converging sum (this is obviously converging) is 1/(1-1/10) *9 (the nine in front of the sum) but the sequence also has to include the 0th term which is 9. By plugging in 1/10 and substracting you get 1.

Simply put, 0.99999 is the (converging) sum of a sequence and by taking it to infinity, you're basically saying it's equal to one.

There you go. It's surprising I didn't see this answer in this 200+ reply long thread.

>> No.15113710

>>15113658
Oh, no sorry
Didn't mean it as an argument
It's just an opinion
Sorry about that misunderstanding
I should have added "...for my liking" at the end. It is mostly because I am tired I said it.

>> No.15113733

>>15113658
When it comes to the age old "Am I a man dreaming he is a butterfly or a butterfly dreaming it is a man" question. My personal response is that either way things are the same. And either way you're best off assuming whatever reality you're currently in to be real.

"Pain's just chemicals in the brain" and all. It's still pain, it's still useful.

The input that our globs of brain matters gets from the world is all it has. Sure we're technically globs trapped in the dark inside a suit of bone and flesh who never experience anything directly.

Yet your mind and my mind are connecting with each other, sharing thoughts. Imperfectly sure but it's still quite the feat and ignoring it, or dismissing the idea that it might be real, really is missing out a whole lot on simply existing.


Anyway, back to math.

>> No.15113755

>>15113710
>
No problem. No offence taken.
>>15113733
I don't really see that much to argue over in your post so I won't. Enjoy the math.

>> No.15113776

>>15113755
Thank you
Hope you enjoy yourself too

>> No.15113790
File: 324 KB, 882x889, NJW.png [View same] [iqdb] [saucenao] [google]
15113790

>>15111427
This isn't proof. Why? Because there is no reason to assume that arithmetic is well-defined for these infinite decimals or even that this object even exists in any reasonable form. Moreover, the pattern of the listed digits needs to represent the pattern of the digits alleged to exist by "..." as those digits may be calculated by a different algorithm from the the one used to calculate the listed digits or the algorithm used to the generate 0.9999...* just results in the first four digits being 9's while who knows whatever the "rest" of the digits are. Of course, you really can't calculate them all. Second, there is no reason to believe that such the expression 0.9999... actually represents anything meaningful.
>>15113500
>Infinity can be a tough concept to grasp
Infinity is not rigorously defined here and in most circumstances such as this one, it never is well-defined. Moreover, there is no reason to assume
>There is no empty space, only nines
even after multiplying the alleged object as it is entirely unclear whether or not the arithmetic can really be defined given the law of logical honesty. If we're playing this infinity game, then why can't I add 0 to the infinity + 1 slot then and follow the usual rules of arithmetic by 10? There is no reason why I shouldn't be able to from this choice perspective appealed to with these infinite objects. There are an infinite number of digits, but the last one is 0.

>> No.15113815

>>15111209
1/3 = 0.33333333...
and 3*1/3 =1 therefore 0.99999... = 1
at this point if you don't understand this the word retard doesn't even describe you

>> No.15113818

>>15113790
There is no infinity+1 slot
Infinity + 1 is still just infinity.
Per definition, infinite means without end.
So there's a 9 in the way

>> No.15113826
File: 62 KB, 1280x720, maxresdefault-3490073748.jpg [View same] [iqdb] [saucenao] [google]
15113826

>>15111595
Easy :


1/9 = 100/900 = (90 + 10)/(9*100)
1/9 = 90/900 + 10/900
1/9 = 1/10 + 1/90

But...
1/90 = 100/9000 = (90 + 10)/(9*1000)
1/90 = 90/9000 + 10/9000
1/90 = 1/100 + 1/900

Etc. for 1/9000, 1/90000, etc.

Then :
1/9 = 1/10 + 1/100 + 1/1000 + ....
1/9 = 0,1111111....

>> No.15113831

>>15112246
i say, imagine...

>> No.15113873
File: 663 KB, 1421x957, NJWW.png [View same] [iqdb] [saucenao] [google]
15113873

>>15113818
>There is no infinity+1 slot
Not according to modern analysis. Especially when you can just write something like [math] [0,1] \equiv [-\infty, \infty] [/math]. I can simply add a point at the end, call it [math] \infty +1 [/math], noting that since [math]\infty+1 > \infty[/math]. It is consistent with assertions of set theory. Moreover its consistent with analysis
>Infinity + 1 is still just infinity.
There is no reason to assume any such arithmetic here either.
>Per definition, infinite means without end.
Infinite is most clearly defined as "non-finite." However, finite itself is not well-defined either outside of perhaps saying that you can assign a natural number to specify specific elements of an "object" whether its the number of elements in a list or the amount of marbles in a box. "Infinite" in these contexts is solely the negation in these examples of what someone might mean by "finite" that you cannot assign a natural number to the amount of elements of a list or marbles in a box. As such it is logically invalid to assume there is such a number or quantity called [math] \infty [/math] or to speak about properties of this thing when it only exists as a logical negation of a very specific property. Either you can do something, or you can't. Finite means you can do something "infinite" only means you can't do that thing.

>So there's a 9 in the way
Except there isn't as before, I showed that according to modern set theory and the axiom of choice we can introduce a unique object called [math] \infty+1 [/math] to the natural/real number line which is greater than [math] \infty [/math] which leads to a 9 in the [math] \infty +1 [/math] place of the number. Hence when we multiply by 10, we move the [math] \infty +1 [/math] 9's up a decimal place so that the [math] 9 [/math] is in the [math] \infty th [/math] decimal place while now we write [math] 0 [/math] in the [math] \infty + 1 [/math] decimal place.

>> No.15113892

>>15113873
By definition, infinity + 1 equals infinity
It is bigger than the biggest number.
In fact, it isn't a number at all. It is literally everything, the set of sets.

Just like there is no biggest number, there is no end to the nines. That's what the three dots represent.

Infinity is not finite, not constrained. It has no end. It can't be treated like a number.

>> No.15113902

>>15113892
>there is no end to the nines.
0,999999...

>there is a 9 at infinity.
0,99999...9

Not the first Anon, but here is his mental gymnastic he cant do :
Both are the same.

0,99999...9 = 0,999999...

>> No.15113907

>>15113902
Those are not the same

One is finite, the other is infinite

>> No.15113916

>>15113902
There exists no point that is infinity. It isn't a place that can be reached. Just like there exists no biggest number.

>> No.15113918

>>15113907
>One is finite
Hmmm... which 1 ?

>> No.15113935

>>15113918
The one that has an end.


Infinity isn't a number. Which is exactly why 0.999... is just a different way of writing 1.0

There is nothing to separate them, infinite nines leaves no possible space for anything to be placed inbetween them. To separate them

>> No.15113950

>>15113935
There simply exists no way to tell them apart. They are completely identical

>> No.15113954

>>15113935
>The one that has an end.
...at infinity.

Dont know for you, but for me, something that has an end at infinity is literally infinite by definition.

>> No.15113957

>>15113918
>which 1 ?

Subtle :)

>> No.15113959
File: 185 KB, 835x893, 1649880599985.png [View same] [iqdb] [saucenao] [google]
15113959

>>15111209
>Prove it robustly without a bunch of algebra

>> No.15113966

>>15113954
You can never reach infinity

It's why 0.000... doesn't work. Like this it's just zeroes nothing else. And that's just 0.
But if you add a 1 at the *end*

0.000...01, suddenly you don't have enough zeroes! I can just keep adding nines forever. Running away from the one. Infinity can't end, per definition. There exists no infinitieth point on the chain because if you can add something new beyond it, then it wasn't infinite.

>> No.15113974

>>15113892
>By definition, infinity + 1 equals infinity
Nope. It doesn't.
>It is bigger than the biggest number.
There is no such thing as a number called infinity, hence it cannot be compared to any other number. However, assuming such a thing
>In fact, it isn't a number at all. It is literally everything, the set of sets.
The idea of a "set of sets" or ever further, a "set of all sets" which would be what is typically asserted as a maximal element in these set theoretic concerns and the analytic concerns when one approaches the extended real number line [math] [-\infty, \infty] [/math] leads to the Russel paradox. The Russel paradox would rather imply that there is no such thing as an infinity as it would be as asserted here, be the maximal set containing all sets, yet cannot contain itself else it would not be maximal.

The fundamental problem here on your part as well as modern math is a sever misunderstanding of foundational concerns. You CANNOT assert there is such an object called infinite or that one can create such an object that has an "infinite" number of elements or anything else along those lines. The fact that you cannot assign a natural number to the total number of natural numbers for example does not imply there is such thing as an infinite. A negation of a positive statement does not posit the existence of an object.
>Just like there is no biggest number, there is no end to the nines. That's what the three dots represent.
And that infinite is bounded as the assertion [math] [0,\infty] \equiv [0,1] [/math] implies. So there is 0.9...9 and the dots represent an infinite number of 9's between the first and [math] \infty[/math]th decimal place.

>> No.15113984

>>15113974
Kinda showcases that math is imperfect doesn't it? And can't adequately be used to represent everything

>> No.15113994
File: 97 KB, 720x540, NJW.jpg [View same] [iqdb] [saucenao] [google]
15113994

>Infinity is not finite,
Again, the ability to assert that there is a logical negation of a term i.e. finite is negated by infinite/non-finite. Does not imply the existence of a number called infinity and is not justification of such a thing. Rather paradoxes like the Russel Paradox or various other paradoxes derived from modern set theory like the Banach-Tarski paradox prove there logically cannot be objects as assuming their existence leads to blatant logical contradictions.

Finite only means that a natural number can be assigned to the quantity of objects of a certain type in this context. Infinite, being the negation implies that a finite-number cannot be assigned a natural number. The fact that there is a negation again does not imply the exist of an object called infinity. It does not imply anything like
>not constrained
>It has no end.
as you are positing. At best, it means that an additional digit or an additional element can be added
>It can't be treated like a number.
Rather there is no such thing as an object called infinity in this context. Plain and simple.
>>15113984
Absolutely. Much of modern math is a shellgame.

>> No.15114015

>>15113994
Woah woah woah

I never claimed there to exist a number called infinity. It's not an object. Thinking of it like one is part of the issue you're having I think.

You're probably better off thinking of it as a limit.

>> No.15114059

>>15114015
>It's not an object.
There is no such thing as infinity.
>Thinking of it like one is part of the issue you're having I think.
The problem's are on your part because there is no such thing as infinity yet you keep trying to pretend there is or using the term in some loosy-goosy undefined fashion. Then when push comes to shove you try to move the goalposts and change what you mean
>You're probably better off thinking of it as a limit.
As if I'm supposed now treat this on the same footing as limits like 0 as the limit to a sequence [math] x_n = 1/n [/math] or as an upper bound like [math] 1 [/math] is to the set [math] [0,1] [/math]. In which case you're tell me to treat it as a mathematical object. Yet then you say it's not an object. Do you even realize the contradictions you're spouting? Either its a mathematical object or it has no place in mathematics as it cannot described in terms of mathematical objects. You've already claimed that it's a "set of all sets" in which case it would be a mathematical object as a set is supposed to be a mathematical object in Cantor or ZFC set theory.

>> No.15114066

>>15114059
Infinity is simply a representation of something never ending.

0.999... has no last 9 and no more numbers can be added to it. It's what 0.999... means.

If you don't want to wrap your head around something that does not end. Eh, be my guest I suppose.

>> No.15114082

>>15113494
Remainders only exist in integer arithmetic. For rational numbers, remainders don't exist.

>> No.15114124

>>15114059
What's the cardinality of the set containing all real numbers?

>> No.15114325

>>15113522
0.00.. and then a 1
-0.00... and then a 1

>> No.15114327

>>15114325
You never reach the one
You need more zeroes

>> No.15114334

>>15114327
you do. you can literally see the 1s there

>> No.15114361

>>15114334
If you can see the one you haven't gone far enough.

See, let's rake this a step at a time

1 - 0.9 = 0.1 right? But whoops there was another nine there we missed. Silly us
So it's actually 1 - 0.99 = 0.01 ah but shoot, missed yet another nine!

And so on. There is no end to the nines, they will keep running away from you and you will never reach the solution you're after. You'll never reach the final one, it doesn't exist.

>> No.15114408

>>15114361
but if somehow this calculation did take place:
1 - 0.999... =
what would the result be

>> No.15114436

>>15114408
0 obviously since 1=0.999...

>> No.15114449

.999... does not exist, infinity is not actually a real number.

But as .999 increases, the value infinitely approaches 1, so that's why it's considered to be 1, that's the limit...

For example
1 - 0.9 = 0.1.
1 - 0.99 = 0.01
1 - 0.999 = 0.001

The pattern keeps repeating as the difference between 1 and 0.999... approaches ZERO. So the limit of 0.999...n... as it approaches infinity is 1.

Now go to bed.

>> No.15114466

[math] x = 0.999... [/math]
[math] x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9}{10^k}[/math]
[math] 10x = 10 \times \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9}{10^k} [/math]
[math] 10x = \lim_{n\rightarrow \infty} 10 \times \sum_{k=1}^{n} \frac{9}{10^k} [/math]
[math] 10x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9\times 10}{10^k} [/math]
[math] 9x = 10x - x [/math]
[math] 9x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9\times 10}{10^k} - \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9}{10^k} [/math]
[math] 9x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9\times 10}{10^k} - \sum_{k=1}^{n} \frac{9}{10^k} [/math]
[math] 9x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9\times 10}{10^k} - \frac{9}{10^k} [/math]
[math] 9x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9\times 9}{10^k} [/math]
[math] x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9\times 9}{10^k} \times \frac{1}{9} [/math]
[math] x = \lim_{n\rightarrow \infty} \sum_{k=1}^{n} \frac{9}{10^k} [/math]
[math] x = 0.999... [/math]

>> No.15114469

>>15114436
No. 1=1
Even captcha says KYSPJT

>> No.15114660 [DELETED] 

>>15112598
>By induction
See >>15114466
>By appeal to intuition
You cannot divide a bottle of water into 3, you can divide the volume of the bottle of water into 3.
From the start a volume can only be expressed in a dimension corresponding to a volume, something like meters cubed, milliliters etc.
You can also divide the mass of the water contained into three smaller bottles so they each weigh the same. Those are two different units defined in two different dimensions.
There is "one bottle" but there is no "1/3" of a bottle. There is "1/3 of the volume of the bottle", "1/3 of the weight of the bottle", "1/3 of the radius of the bottle etc".
In the world of natural numbers 1 divided by 3 equals 0, if you split one bottle into three there is no bottle left.
>By convergence theorem
There is a difference between "converges to" and "equals".
Like I said before there are real numbers between 0.999... and 1.

>> No.15114704

>>15114466
That's utterly inconclusive, but nice triple dubs. This can still show that 0.999...=1
[math]10x=lim_{n\to\infty}\Sigma^{n}_{k=1}\frac{9*10}{10^k}[/math]
[math]10x=lim_{n\to\infty}\Sigma^{n-1}_{k=0}\frac{9}{10^{k-1}}[/math]
[math]10x=9+lim_{n\to\infty}\Sigma^{n-1}_{k=1}\frac{9}{10^k}[/math]
[math]9x=10x-x[/math]
[math]9x=9+lim_{n\to\infty}\Sigma^{n-1}_{k=1}\frac{9}{10^k}-lim_{n\to\infty}\Sigma^{n}_{k=1}\frac{9}{10^k}[/math]
[math]9x=9[/math]
[math]x=1[/math]

>> No.15114714

>>15114704
Actually, to refine it, I should have simplified
[math]9x=9+lim_{n\to\infty}\Sigma^{n-1}_{k=1}\frac{9}{10^k}-lim_{n\to\infty}\Sigma^{n-1}_{k=1}\frac{9}{10^k}[/math]
to
[math]9x=9-lim_{n\to\infty}\frac{9}{10^n}[/math]
or
[math]x=1-lim_{n\to\infty}\frac{1}{10^n}[/math]
Which yields
[math]x=1[/math]

>> No.15114754

>>15111209
Here’s the simplest argument if you actually know basic real analysis.
0.99… is a real number. For any real numbers a and b, if a<b, then there exists real number c such that a<c<b. Suppose 0.99… < 1. Then there must be some real value x such that 0.99… < x < 1. Notice that 0.99… = sum of (9/10^i) as i goes from 1 to infinity.
Since all real values can be defined as an infinite decimal expansion, and x < 1, we can define x by the infinite sequence Sn such that x = sum of Si/10^i as i goes from 1 to infinity. Define 0.99… similarly, using the sequence Tn instead. It is trivial to see that, for all i, Ti = 9. Also note that for all i in [1, infinity), 9 >= Si. But in order for 0.99… > x to hold true, there must exist at least some i in [1, infinity) such that Si > Ti. Obviously none exists, since as stated before, Si <= 9 = Ti for all i in [1, infinity). This is a contradiction, and therefore no such value x exists, and therefore 0.99… = 1.
In simpler terms for brainlets, 1 is not less than 0.99…, and there is no space between 0.99… and 1 for a single real number to exist, so therefore they must be equal.
If you don’t understand why the statement “for all a, b in R, if a<b then there exists c in R such that a<b<c,” then you have not studied enough basic fucking mathematics to discuss the question of 0.99… = 1. Might I recommend baby Rudin, or maybe a basic proofs textbook if the words in baby Rudin are too big for you?

In short, people who say 0.99… =/= 1 after seeing a legitimate proof either don’t know what a real number is, are fucking retarded, or don’t believe in the real numbers/infinite sequences. All 3 of these are good reasons to ignore these people.

>> No.15114759

>>15114754
> But in order for 0.99… > x to hold true
Typo. Meant “<”

>> No.15114763 [DELETED] 

>>15114754
>In simpler terms for brainlets, 1 is not less than 0.99…, and there is no space between 0.99… and 1 for a single real number to exist, so therefore they must be equal.
They're not equal, but because they approximate each other, under any meaningful level of precision the results of doing mathematical operations with either number will have the same result. You can only discern the difference with infinite precision and that's not useful.

>> No.15114776

>>15111209
1/3 = 0.33333....
multiply both sides by 3 to get
3/3 = 0.9999999...
1 = 0.999999999....

>> No.15114802

>>15114776
>1/3 = 0.33333....
This is not true tho, there is always 1/3 missing

>> No.15114871

[math]
x= \frac{1}{10} \\
0. \overline{9}=9x+9x^2+9x^3+9x^4+ \cdots \\
0. \overline{9}=9x \left (1+x+x^2+x^3+ \cdots \right ) \\
0. \overline{9}=(1-x) \left (1+\mathbf{x}+x^2+\mathbf{x^3}+x^4+ \cdots \right ) \\
0. \overline{9}=1-x+ \mathbf{x-x^2}+x^2-x^3+ \mathbf{x^3-x^4}+x^4-x^5+ \cdots \\
0. \overline{9}=1
[/math]

>> No.15114965

>>15114408
0.00... and then a 1

>> No.15114973

>>15114776
first of all 0.333... is assumed irrational

>> No.15114974

If you allow 1 to be 0.999999
Then then you allow every real number = 0.000....1 less than itself
If you add a bunch of them, the error becomes significant
Math is a scam
wake up, sheeple.

>> No.15114991

https://youtu.be/jMTD1Y3LHcE

>> No.15114997

>>15114973
irrational means no pattern.
>0.333333333..........
see a pattern?

>> No.15116018

>>15111209
Fun fact: 0.9999... is not equal to one using the original purpose of the ellipsis (...) symbol (extend series elements infinitely). They literally changed the ellipsis symbol to mean taking the limit for these sorts of numbers because instead of clearing up confusion, math tards would just go ahead and change the definition so not to be wrong.

>> No.15116070

>>15113733
I don't exist tho.

>> No.15116077

>>15113480
It's arithmetic retard, algebra involves variables.

>> No.15116090
File: 266 KB, 1024x1024, 1673385007406.jpg [View same] [iqdb] [saucenao] [google]
15116090

>>15111279
based retard

>> No.15116563

>>15114776
Saying 1/3 = 0.333... is simplifying the truth, if you do the division algorithm you'll always get a remainder, no matter how much you divide.
That remainder is [math] 0.000... = \lim \frac{1}{10^n} [/math]
So 3 * 1/3 = 3*0.333... + 0.000.. because that is how whole number division works.

>> No.15116580

>>15114974
But 0.0...001 doesn't exist because I can always add another 0

>> No.15116582
File: 19 KB, 665x326, 10400000..png [View same] [iqdb] [saucenao] [google]
15116582

quints have already decided this

>> No.15116593

Also 0.000... is not zero.

[math] \lim 10^n \times 0 = 0 [/math]
[math] \lim 10^n \times \lim \frac{1}{10^n} = \lim \frac{10^n}{10^n} = 1 [/math]

>> No.15116600
File: 279 KB, 1120x935, 1672142095616034.jpg [View same] [iqdb] [saucenao] [google]
15116600

0.999... is a cycling number.
It doesn't equal 1, it almost equals 1 but infinitely so, thus, sometimes it WILL equal 1. There is a 'linking' almost increase event hidden in that symbol.

/Thread

>> No.15116602

>>15116600
You're missing 3 numerals in your base 10 retardation otherwise it would make sense. Now if you would please get.. the fuck... Off mah sci

>> No.15116611

>>15116593
That's because are you retarded the first 0.0 is the thing that's positively increasing with additional .00 .000 so 0.0000 is moving away from 0. This is proof that the LateX users are just retards hidden behind intolerable nonsensical language/code. Fuck off mah sci now

>> No.15116615

STOP THIS NONSENSE ON MAH SCI NOW STOP POSTING STOP TROLLING STOP WHINING, ITS CHILDISH

>> No.15116683

>>15111209
ITT: filtered real-analysis brainlets and midwits who couldn't pass real-analysis class dishonoring Chad ultrafinitists like Wildberger, who could easily pass a real-analysis class if he wanted to.

>> No.15117293
File: 244 KB, 1080x1559, 1600622970116.jpg [View same] [iqdb] [saucenao] [google]
15117293

At where is the practical delineation line between 0.999... and 1? At what resolution do the practical limitations of reality make the distinction inconsequential under all possible circumstances?

>> No.15117525

>>15111209
>Creating thread about [math]\frac{3}{3}[/math] over and over, for years
Definition of insanity

>> No.15118043

Wonders of mathematicians
>We can proof that there is 927n^8-ei dimensions using blurgh, blargh and gnarl.
>Cannot see that 1/3 is not 0.333... but only the closest approximation when using decimals and whole numbers

>> No.15118046

>>15118043
how close is this approximation? what is missing?

>> No.15118057

>>15118046
>How close
Very close but not exact/precise
>Whats missing
1,2,3
4,5,6
7,8,9
0 <-
How to group 10 things into thirds

>> No.15118072
File: 71 KB, 976x709, 31252.jpg [View same] [iqdb] [saucenao] [google]
15118072

>ITT: highschool dropouts cannot fathom a simple definition

>> No.15118082

>>15118057
>Very close
Is there some even better approximation?

>> No.15118091

>>15118082
Yes, forexample using different bases.
0.333.., 0.666.., 1 for base 9
0.444.., 0.888.., 1 for base 12

>> No.15118093

>>15118091
made an oopsie.. these threads are just so retarded..
0.3, 0.6, 1 for Base9
0.4., 0.8, 1 for Base12

>> No.15118132

>>15116563
Since the tree dots denotes etcetera, isn't 0.000... just an infinite string of zeroes?

i e zero

>> No.15118582

>>15114066
>Infinity is simply a representation of something never ending.
>never ending
Ah yes, the resort to even more pseudo-scientific nonsense. There is no such thing as an infinity.
>0.999... has no last 9 and no more numbers can be added to it. It's what 0.999... means.
If we were to apply the standards of analysis and set theory and write the extended natural numbers in interval for, [math] [1, \infty] [/math] there is an upper bound called [math] \infty [/math] so there is an [math] \infty[/math]th decimal place which contains a 9. This is the last 9 to the alleged number with an infinite number of 9's "0.999..." = 0.999... 9. So 10* 0.999 = 10* (0.999...9) = 9.999...0.
>>15114124
There is no such thing a "real" number. There is no such thing as a "set" as you have not defined it and no mathematician has ever defined it.

>> No.15118602
File: 194 KB, 1284x1233, 210AB981-8145-4B64-A0C1-C5AEF9DECA1F.jpg [View same] [iqdb] [saucenao] [google]
15118602

>>15111209
Technically, don’t we have multiple infinities as we approach zero in all directions? Couldn’t this just be the beginning of infinity? Last time I checked, one is not infinity. Doesn’t this make you all morons for not thinking that?

>> No.15118627

>>15118602
No. There are no infinities. Your graph ends at explicit points.

>> No.15118629

>>15118582
The interval can't be closed
[1, infinity] doesn't make sense
Has to be [1, infinity [

Since there is no upper bound

>> No.15118633

>>15118582
Alright simpler words then.

How many numbers are there?

>> No.15118639

>>15118627
I guess you’re a literal retard that can’t conceptualize simple ideas. It projects infinite both ways.

>> No.15118641

>>15118629
Not according to modern set theory and analysis. It can be closed and it is closed.
>>15118633
There are only as many numbers as those which has been explicitly written down.

>> No.15118644

>>15118629
Brainlet who doesn't know what compactification is.

>> No.15118646

>>15118639
>can’t conceptualize simple ideas
Rather that's you as you're taking a simple idea from geometry, that something simple like a curve or line segment can be extended, and then in your lack of understanding that it's simply as its stated, need to imagine there must now be objects out the exist out of nowhere called "infinities" when this doesn't even logically follow.

>> No.15118656

>>15118641
For any such number that has been written down I can write down a bigger one.
How many numbers are there?

Per definition, infinity is unbounded. The only characteristic of it is that it is not finite. Making it finite makes it ininfinite.

Are you sure that compactification is useable here in this context? That we'll still get the same results?


Like I get that you just hate the whole concept of infinity and think it shouldn't exist. But excluding it really causes you to beat around the bush or to redefine it. Which is weird.

>> No.15118662

>>15118646
> [-infty,+infty]
> affinely extended real number system
I was pointing out a possible scenario where 0.9999999 isn’t one. Seethe more.
https://en.m.wikipedia.org/wiki/Extended_real_number_line
https://mathworld.wolfram.com/AffinelyExtendedRealNumbers.html

>> No.15118673

>>15118662
>"The normal nonsense isn't good enough so I have to make up more nonsense"
You really are a retard.

>> No.15118679

>>15118673
Thanks! I’m trying

>> No.15118691

>>15118656
>For any such number that has been written down I can write down a bigger one.
Then write it down and I'll say that number exists. Until you write it down it's nothing but talk and therefore meaningless.
>How many numbers are there?
Only the amount of numbers that have been explicitly written down.
>Per definition, infinity is unbounded.
There is no such thing as an infinite
>The only characteristic of it is that it is not finite
Define finite. The only possible definition is something like you can assign a natural number to it in an appropriate fashion like the number of marbles in a box. In this case infinite (which is not the same thing as this fictional "infinity") is just the logical negation of finite. That means exactly that you cannot assign a natural number. This does not justify the assumption that an object (or whatever nonsense is posited) called "infinity" exists.
>Are you sure that compactification is useable here in this context?
According to the axiom of choice, it is usable here in this context.
>That we'll still get the same results?
We get the result that 1-.999... = 1.000...00-.999...99 = 0.00...01 by the axiom of choice.
>Like I get that you just hate the whole concept of infinity and think it shouldn't exist.
The reality is that there is no such thing as an infinity in these contexts.
>But excluding it really causes you to beat around the bush or to redefine it
Incorrect. Whatever the term "infinity" refers to is undefined it is not justified in these contexts and it still isn't. Whereas "infinite" ([math] \not= [/math] infinity) is just the logical negation of finite. Finite itself needs to be defined rigorously such as in the case where finite means you can count some number of objects like the number of marbles in a box.

>> No.15118697

>>15118691
> Whatever the term "infinity" refers to is undefined
Isn’t this statement your opinion and not universally agree to it, I.g. Cope?

> However, the expressions +infty+(-infty), -infty+(+infty), and 0/0 are undefined. The above statements which define results of arithmetic operations on R^_ may be considered as abbreviations of statements about determinate limit forms. For example, -(+infty)=-infty may be considered as an abbreviation for "If x increases without bound, then -x decreases without bound." Most descriptions of R^_ also make a statement concerning the products of the improper elements and 0, but there is no consensus as to what that statement should be. Some authors (e.g., Kolmogorov 1995, p. 193) state that, like +infty+(-infty) and -infty+(+infty), 0·(+/-infty) and +/-infty·0 should be undefined, presumably because of the indeterminate status of the corresponding limit forms. Other authors (such as McShane 1983, p. 2) accept 0·(+/-infty)=+/-infty·0=0, at least as a convention which is useful in certain contexts.

>> No.15118699

>>15118691
Then you admit you have no clue how many numbers exist.

If we don't know how many nimbers exist, how can we prove something is true for all numbers?

>> No.15118701

>>15118691
All I'm asking of you is to tell me how many nines 0.999... has

>> No.15118706

>>15118691
It seems to me like you've gone and cherrypicked a couple of axioms and definitions you believe in. Completely disregarding the current case.

Name what writing 0.999... means.

>> No.15118713

>>15118701
The 0.99999 increase without bounds, how’s that?

>> No.15118726

>>15118697
>Isn’t this statement your opinion and not universally agree to it
Not an opinion. It's a fact. It does not exist. Moreover, assuming such a thing exists leads to a variety of paradoxes like the Russel paradox.
>>15118699
>Then you admit you have no clue how many numbers exist.
In the context where one can introduce one more number into a list from an algorithm, then there is no such thing as the "number of numbers."
>If we don't know how many nimbers exist, how can we prove something is true for all numbers?
You don't need to know anything about how many numbers exist or anything along those lines to prove something is true. It's simply using a generic placeholder to do a form of algebra or logic. The number of objects of a certain type is never needed.
>>15118701
There are three 9's.
>>15118706
>It seems to me like you've gone and cherrypicked a couple of axioms and definitions you believe in
I don't believe in those axioms. But since they are believed in by contemporary mathematicians, I'm going to use them. The Axiom of Choice does infer that a decimal supposedly consisting only of an infinite number of nines to the right of the decimal place in fact has a final 9.
>Name what writing 0.999... means.
In terms of what it actually means, you wrote 0, a period, then three nines. After which "..." is just a placeholder for all sorts of fancy. In fact, without further specification, it means either nothing or that I can simply add on whatever digit I please after the first three 9's.

>> No.15118734

>>15118726
> Russell Paradox
Interesting thank you

>> No.15118919

>>15111209
you're correct 0.999... is not a number and thus not 1

>> No.15119387

>>15111209
I will say, it can never be 1 and thats just how it is.

>> No.15119561

literally what is the point of calculating involving anything less than the planck constant. useless metaphysics shit

>> No.15120402 [DELETED] 

>>15111209
If two numbers are unequal, then there must be a number between them.

There are clearly no numbers between 0.999... and 1.

Therefore, 0.999... and 1 must be two representations of the same number.

Case closed.