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/sci/ - Science & Math


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12272392 No.12272392 [Reply] [Original]

How do I measure the capacitance of a capacitor without using a multimeter?
I have a differential voltage meter, a voltage source and logging shit on the computer.

The joke is that I used to know how to do this. I have some old pics on my computer about how I did it, but my notes are so messy I can't even read them.
This photo has something to do with it. For some reason I've plotted potential vs time and fit a line somewhere.

>> No.12272399

>>12272392
RC time constant. Square wave -> LPF -> oscope. Measure the time taken to reach 2/3rds the square's height

>> No.12272986

>>12272399

Wut.

>> No.12273014

>>12272986
alternatively, you could take a known inductor, || it with the cap and send fast pulses over it. Measure the ringdown frequency and calculate C using [math]f = \frac{1}{2\pi \sqrt{LC}}[/math]

>> No.12273165

I usually just read the label

>> No.12273300

>>12272392
with a tangent on the charging/discharge slope you can get t_0 and calculate the capacitance
its 1 mF?

>> No.12273377

>>12272986
ln(2)=0.69314718056

>> No.12273540

>>12272392

Charge cap . Log voltage. Integrate over time

I=C*dVc/dt

Vsource=Vr +Vc differentiate
0=dVr/dt+dVc/dt
0=dIR/dt+I/C. Solution is exponent
I=a*e^(t/RC)
I=Vr/R
Integrate over Vr/R
Integrate(Vr/R)
Integrate(I)
Integrate(a*e^(t/RC))=a*e^(t/RC)/RC
Divide by Vr/R
(Vr/R)/Integrate (Vr/R)=RC
C=Vr/(R*Integrate (Vr,t))

>> No.12273766

>>12272392
this sounds naive but couldn't you just use a constant voltage on a 0 resistance circuit with just the capacitor, measure the charge after the capacitor is fully charged, and use the equation C=Q/V?