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/sci/ - Science & Math


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File: 185 KB, 386x370, Screen Shot 2022-06-28 at 6.22.56 PM.png [View same] [iqdb] [saucenao] [google]
14610207 No.14610207 [Reply] [Original]

can /sci/ find the area of the triangle?

>> No.14610210

>>14610207
circle has a radius of 1, and the triangle is equilateral on all sides

>> No.14610224
File: 69 KB, 741x568, FCwMTbyXMAILAnk.jpg [View same] [iqdb] [saucenao] [google]
14610224

>>14610210
Let's make this a bit more difficult. What if you have the radius of the sphere and the spacial coordinates of the four vertices as variables.

>> No.14610250

>>14610207
Is it 1/2 unit volume?

>> No.14610251

>>14610207
3?

>> No.14610252

>>14610224
If you have the coordinates of the vertices then it's trivial and just a tedious CSesque problem

>> No.14610274

>>14610207
>triangle

>> No.14610295

>>14610207
bump. I will be waiting for an answer when I wake up

>> No.14610319

>>14610250
Okay I change my mind 1/3 unit volume

>> No.14610320

>>14610207
Area of a 3 dimensional solid? you mean volume.
Equilateral on all sides? you mean equilateral.
Please leave.

>> No.14610333

>>14610252
How do you make OP's question less trivial. If the shapes are equilateral triangles then it's even more trivial.

>> No.14610381

>>14610207
0.43301169914

>> No.14610529

>>14610207
can op guess what number I'm thinking of?

>> No.14610631 [DELETED] 

>>14610207
>area
>triangle
>circle
Those are 3d objects you retard. Not solving your problem.

>> No.14610633

>>14610207
>area
>triangle
>circle
Those are 2D Objects you retard. Not solving your problem.

>> No.14610635

>>14610320
So many assumption about OP and so little truth

>> No.14611650

really? nobody has solved this yet?

>> No.14611821

>>14611650
I did though
>>14610381

>> No.14613502

>>14610207
after thinking about it for 15 min I think I would turn the triangle into a cone, find ratio of height to base radius, then take that ratio and find some intercepts on a unit circle, that would give me the cone radius, find a side length X of an equilateral triangle in that cone base which is exactly a length X of a side in OP's tirangle, then just find the surface area via 4x of those triangles with length X. Maybe would take an hour.

>> No.14613511

>>14611821
Close.
0.425382538154419

>> No.14613550

there are 4 triangles in that picture retard, which one?

>> No.14613553

>>14610320
he didnt say pyramid he said triangle retard fag
>>14610529
5

>> No.14614191
File: 19 KB, 269x283, 1629398891973.jpg [View same] [iqdb] [saucenao] [google]
14614191

>>14610320
>area
Of the triangle, retard. One side of the tetrahedron. They are all the same so they have the same area, problem?
>equilateral on all sides
All sides of the tetrahedron are equilateral. Equilateral triangles. It's equilateral on all sides.
>please leave

>> No.14616433

>>14614191
>the triangle
>the
There is more than one triangle retard
>problem?
No not at all, "the triangle" is still an irrelevant statement since there is no "the triangle" in the OP picture in fact there are 4 triangles
>please leave
no you redd*t fag

>> No.14616449
File: 26 KB, 128x128, 1636718723789.png [View same] [iqdb] [saucenao] [google]
14616449

>>14616433
>get BTFO
>proceed to unforced reddit mention

>> No.14616955

>>14616449
Except I am >>14616433 and I am not >>14610320 and you did not "BTFO" me, faggot. Now go back to redd*t

>> No.14617000
File: 49 KB, 600x600, 1626206944041.jpg [View same] [iqdb] [saucenao] [google]
14617000

>>14616955
>I'm obsessed with reddit, but maybe if I type r*ddit instead people will think I'm cool and that I hate reddit

>> No.14617062
File: 222 KB, 640x640, 1580862693462.png [View same] [iqdb] [saucenao] [google]
14617062

>>14617000
>being this new