/sci/ - Science & Math

Yeah come to think of it, the smoother variant to pin it down would be

[math]1=\frac{A+U}{A+U}=\frac{A}{A+U}+\frac{U}{A+U}[/math]

and let [math]A=x^2[/math] and [math]U=-4[/math].

which I now realize is a very specialized case of the matrix inversion lemma
https://en.wikipedia.org/wiki/Woodbury_matrix_identity

[math] \left(A + UCV \right)^{-1} = A^{-1} - A^{-1}U \left(C^{-1} + VA^{-1}U \right)^{-1} VA^{-1} [/math]

Which isn't unrelated to my question yesterday
>>12465861

[math] \frac{{\mathrm d}}{{\mathrm d}x} (x\mapsto x) = 1 [/math]

>Cuts through the hard problem of consciousness
Whitehead was truly ahead of his time.

yup

Tell me about Alfred North Whitehead