/sci/ - Science & Math

>>11790300
What is the highest order of any of the elements in your group? Find that, embed accordingly. You will notice that this is minimal because any smaller symmetric group would lack elements of that order.

>>11762337
[math]\sqrt{0}[/math] is the best prime.

>>11762370
Now that you [math]n(n+2p) = q^2[/math] for some prime [math]q[/math], you have either [math]n=1[/math] or [math]q[/math] dividing both [math]n, n+2p[/math] (try to figure out why). If we assume that [math]q[/math] divides them both, then [math]n=aq, n+2p = bq \Rightarrow q^2 = n(n+2p) = abq^2 \Leftrightarrow a=b = \pm 1[/math], but then [math]n = n+2p \Leftrightarrow p = 0[/math], not nice. Thus, [math]n=1[/math], and so you should now try to check if [math]q^2 = 2p+1[/math] makes any sense. (I hope I didn't make any dumb mistakes)