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>> No.8998446 [View]
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8998446

>>8998096

If you do that, you have to reference 4.5V as your ground in the circuit and pretend the true ground is -4.5V.

>>8997638
>a small signal of ~150mV AC goes in, and a half-wave rectified and filtered DC output of about 2.8V should be the result (when the voltage divider pot on the output is set to 5k ohms).

Too much amplification. If you forget about the rectifying and filtering on the output, the output will be 100 times the "0.150V" input which is "15V" peak (or "21V" peak if that input is in RMS). The upper rail is only "4.5V" so you're way beyond saturated.

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