/lit/ - Literature

>>10437780
>>10437798
Good news! You're both wrong and right. Mostly right, though, don't worry. You can write the limit of this function as EITHER
lim x->0 -1/(x^2) = -infinity
OR
lim x->infinity -1/(x^2) = 0
OR
lim x->-infinity -1(x^2) = 0
Because it's basically got three limits. For one, the function f(x) will never equal 0, for obvious reasons (there's a 1 in the numerator, so it will always be one of SOMETHING, and no dividing by 0). So 0 is the limit of the function as x goes to infinity or -infinity.
And since the function is also decreasing rapidly without bound as x gets closer to 0 (the smaller the denominator of a fraction is, the greater the magnitude of said fraction -- 1/7 is greater than 1/15, which is greater than 1/1000 -- but since this is a negative fraction no matter what, that tremendous magnitude will actually be directed in the negative direction and the quantity will actually DECREASE as the magnitude increases), you could also say: as x goes to 0, the function has no lower bound as it decreases. Think of it like an intense, raging alcoholic who just continues on an endless downward spiral with no limit whatsoever, no end in sight, no support system to help him get out of it, until it all just abruptly stops (does he shoot himself? die from alcohol poisoning? You be the judge). So, as x goes to 0, the limit is -infinity.
So, the meme is correct, you guys are correct, everyone is correct! Woo hoo!
I highly suggest Wolfram Alpha for further adventures into the world of mathematics. This invaluable tool can basically do anything you ask it.
Happy trails!
t. /sci/