/jp/ - Otaku Culture

[Anonymous No.]

[Anonymous No.]

"kilometers an hour"

Brits get out

[Anonymous No.]

Only Yukari can leave and enter Gensokyo as she wishes.

[Anonymous No.]

There are no buses in gensokyo, baka

[Anonymous No.]

>>9167506
i dopnt have paper

[Anonymous No.]

They won't. Why would Shizuha be out in the summer?

[Anonymous No.]

Cirno melts from heat generated by atmospheric friction before she ever meets up with Meiling.

Problem solved. Give me my cookie.

[Anonymous No.]

>>9167512
European schools teach British English.

[Anonymous No.]

>>9167506
here you go OP

http://www.wolframalpha.com/input/?i=300%2F48%28x%29%3D-300%2F108%28x-300%29

92.3 meters

learned in hightscool xD

[Anonymous No.]

>>9167558

the point is to solve the math. no cookie for you.

[Anonymous No.]

>>9167582
You can't be bound by common sense in Gensokyo.

[Anonymous No.]

>>9167569

Fine.

"kilometers an hour"

Europe get out

[Anonymous No.]

>>9167589

Don't give me that slutty philosophy

[Anonymous No.]

2.11 hours.

[Anonymous No.]

>>9167506
They'll meet at 14:10. I honestly took far too long to solve such a simple question.

[Anonymous No.]

Also there are no distinct variables. Was there a headwind? Did they stop for coffee? Do their frilly clothes add drag?

[Anonymous No.]

>>9167589

i'll give you a 1/10. that's the best i can do.

[Anonymous No.]

http://www.wolframalpha.com/input/?i=1%2F48%28x%29%3D-1%2F108%28x-300%29

1.92 hours

lel, I leard that in highscool xD

[Anonymous No.]

14:10 more or less, too lazy to use calculator

[Anonymous No.]

[Anonymous No.]

disregard question grope keine tits

[Anonymous No.]

>>9167616
x^2=19^2+19^2
x= sqrt (19^2+19^2)

[Anonymous No.]

There are similar questions in math exam I'm preparing for.

[Anonymous No.]

>Your second favorite touhou is flying in the OPPOSITE DIRECTION

[Anonymous No.]

>>9167626
Then why don't you solve it.

[Anonymous No.]

does gensokyo use the metric system

[Anonymous No.]

>>9167651
yes since they are not amerilard scum

[Anonymous No.]

i remember doing math up until Calculus II, but I forgot most of it.

[Anonymous No.]

you should be able to solve this x-----DDDD

[Anonymous No.]

>>9167665
t+288+238kdwj=9
:----DDDDDDDDDD

ebin

[Anonymous No.]

>>9167645
Because I don't understand that at all.

[Anonymous No.]

12:05

[Anonymous No.]

>>9167673
Alright, anon, listen to this. If you throw an object with a speed of X towards an object, also thrown towards the first object, with a speed of Y, both objects will meet at the same time as in a situation that the first object was thrown with a constant speed of X+Y but the second object was still. If both objects are flying against each other, you can simply add their speed togheter and see it as a single object going towards a goal, which in this case is the distance between both. Then you just divide the speed by the distance and calculate the time it would take.

[Anonymous No.]

they will meet @ 14h 10min 46s 38ms

[Anonymous No.]

>>9167694

Not that person, but thank you for the explanation!

[Anonymous No.]

You didn't give us their initial positions. Is 2hu_A to the east or west of 2hu_B? For all thats given they could be flying away from each other.

[Anonymous No.]

>>9167694
I understand now! Thank you a lot! Now I know that I didn't understand this because things I was learning was about 2 crashing objects too, but it was different.

[Anonymous No.]

derivative it and set equal to zero

[Anonymous No.]

This is a very simple problem. I'm going to solve it using the relative method because it's intuitive.

Mokou is traveling at 34 k/h to Eientei from the edge of the bamboo forest.
Eirin is traveling 108 k/h from Eientei to the edge of the bamboo forest opposite direction to Mokou.

When you're traveling, it seems you're stationary while everything else is moving around you. This means to Mokou, all of the trees and such are traveling 34 k/h toward her while she holds still. But Eirin, who's going directly toward her, seems to be going faster. We calculate how much by adding up their speeds.
This makes a total of 142 k/h. So to Mokou, Eirin appears to be traveling toward her at 142 k/h, and vice versa.
Now we just solve it normally and calculate how long it takes for Eirin to approach Mokou. Distance / rate = time. Therefore, 300 / (142k/h) = 2.112676 hours.
This means it takes about 2 hours and 6 minutes until they meet.

[Anonymous No.]

ｌｉｔｔｌｅ　ｋｉｄｓ　ｓｈｏｕｌｄ　ｊｕｓｔ　ｌｅａｖｅ

[Anonymous No.]

>>9167801
Not everyone is a math wiz, poindexter.

[Anonymous No.]

I am pretty sure I can solve this but I really do not feel like doing any math that I am not required to do so I am just going to say I dont know and be an idiot.

[Anonymous No.]

>>9167815
but this is physics

[Anonymous No.]

>>9167788
you make it seem so easy

[Anonymous No.]

>>9167829
Even worse

[Anonymous No.]

>>9167829
p
h
y
s
i
c
s

i
s

s
t
i
l
l

M-A-T-H

p
o
o
p
h
e
a
d

[Anonymous No.]

>>9167801
looks at this fucking nerd thinking he is the shit because he knows math lmao
better hide your lunch money sperglord

[Anonymous No.]

Wait, what?
It doesn't specify the original location of "2nd favorite touhou" other than being 300 km away from "favorite touhou". This gives "2nd favorite touhou" the possibility of being anywhere in a circle 300 km from "favorite touhou". Because of this, the "2nd favorite touhou" might be BEHIND "favorite touhou", and as such their distances would increase with time as they are moving in opposite direction.

TL;DR: not enough info to solve the problem.

[Anonymous No.]

/jp/ - Science and Math

[Anonymous No.]

108x + 34x = 300

[Anonymous No.]

>>9167839
y

t
h
e

f
u
g

u

t
y
p
e

L-I-K]/spoiler]-E

t
h
i
s
???

xD
X
D

[Anonymous No.]

>>9167850
It is probably implied that both Touhous were going to meet because they are the favorites of the person trying to solve the problem and this person would probably love to see both of his favorite touhous paired togheter as a couple, thus needing to meet.

[Anonymous No.]

What if I only have one favorite touhou?

[Anonymous No.]

I don't have a favourite Touhou, so I guess never.

[Anonymous No.]

what if my second favorite 2hu can stop time?

germany just scored btw

[Anonymous No.]

>>9167896
Then amend the problem. Your favorite touhou and her friend want to meet.

A more complicated problem is that I don't think all touhous can fly.

[Anonymous No.]

2 hours 6 mins 36 seconds

Funny that I have a Relativity exam on Friday...

[Anonymous No.]

[Anonymous No.]

>>9167920
I have arithmetic progression exam tomorrow and I don't know anything at all.

[Anonymous No.]

>>9167960
You should get to study then, anon.

[Anonymous No.]

>>9167920
>>9167960

ITT: we talk about tests we are having tomorrow. My engineering test is in 3 hours.

[Anonymous No.]

>>9167952
My second and third favorite would meet though, they're sisters.

[Anonymous No.]

>>9167984
I have no idea how to prepare for it. I will play Touhou tonight instead.

[Anonymous No.]

>>9167990
Three hours doesn't sound like tommorow. You should go to some other thread.

[Anonymous No.]

>>9167788

that'a a fucking huge forest

[Anonymous No.]

>>9168012
what? just do exercises until your fingers start to bleed

[Anonymous No.]

Never because Gensokyo is flat.

[Anonymous No.]

>>9167627
Yup it can be interpreted in two ways, but seeing as bottom line says to disregard any data which wasn't presented, only one is solvable.

[Anonymous No.]

>>9168011
Flight through bamboo forest of the lost in IN took few hours, so go figure.