/jp/ - Otaku Culture

[Anonymous No.]

Now you realize that Archer's plan to kill Shirou makes no sense, because if Archer kills Shirou, Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou, so Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou, so Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou, so Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou, so Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou, so Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou, so Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou, so Archer will not exist, so he can't go to the past to kill Shirou, so Archer will exist, so he can go to the past to kill Shirou,

[Anonymous No.]

That's the entire fucking point.

He was going to create a paradox in hopes that "Shirou Emiya" will vanish from the Akashic Records.

However, he realized that UBW Shirou would NOT become Archer, so his fight with him was just self-aggression.
He also failed to realize Mind of Steel Shirou's capability, or something.

[Anonymous No.]

That's precisely the paradox that makes his plan work.

[Anonymous No.]

Someone said it had to make sense?

[Anonymous No.]

A hundred prisoners are each locked in a room with three pirates, one of whom will walk the plank in the morning. Each prisoner has 10 bottles of wine, one of which has been poisoned; and each pirate has 12 coins, one of which is counterfeit and weighs either more or less than a genuine coin. In the room is a single switch, which the prisoner may either leave as it is, or flip. Before being led into the rooms, the prisoners are all made to wear either a red hat or a blue hat; they can see all the other prisoners' hats, but not their own. Meanwhile, a six-digit prime number of monkeys multiply until their digits reverse, then all have to get across a river using a canoe that can hold at most two monkeys at a time. But half the monkeys always lie and the other half always tell the truth. Given that the Nth prisoner knows that one of the monkeys doesn't know that a pirate doesn't know the product of two numbers between 1 and 100 without knowing that the N+1th prisoner has flipped the switch in his room or not after having determined which bottle of wine was poisoned and what color his hat is, what is the solution to this puzzle?

[Anonymous No.]

>>2270608

Yes.

[Anonymous No.]

>>2270608
What puzzle?

[Anonymous No.]

>>2270608

[Anonymous No.]

>Fate/Stay Night
>make sense

[Anonymous No.]

>>2270608

Three gods A, B, and C are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is a completely random matter. Your task is to determine the identities of A, B, and C by asking three yes-no questions; each question must be put to exactly one god. The gods understand English, but will answer all questions in their own language, in which the words for yes and no are 'da' and 'ja', in some order. You do not know which word means which.
It could be that some god gets asked more than one question (and hence that some god is not asked any question at all).
What the second question is, and to which god it is put, may depend on the answer to the first question. (And of course similarly for the third question.)
Whether Random speaks truly or not should be thought of as depending on the flip of a coin hidden in his brain: if the coin comes down heads, he speaks truly; if tails, falsely.
Random will answer 'da' or 'ja' when asked any yes-no question

Which combination is the most logical answer?

[Anonymous No.]

Ask "are you going to answer this question with the word that means no in your language," to all three.

[Anonymous No.]

>>2270644
Interesting. True God, of course, wouldn't be able to answer. But I don't think that would distinguish between False and Random.

[Anonymous No.]

>>2270653

>Whether Random speaks truly or not should be thought of as depending on the flip of a coin hidden in his brain: if the coin comes down heads, he speaks truly; if tails, falsely.

If Random doesn't speak, you now have to discern True from Random.

Random speaks Truth and Lies at random, not truly random answers.

[Anonymous No.]

>>2270653
Disregard that. I see now. I glossed over this part: "if the coin comes down heads, he speaks truly; if tails, falsely". I thought Random God would answer "Yes" or "No" randomly, not truly or falsely, randomly.

[Anonymous No.]

>>2270662
>>2270664

Randommind

[White Ren !YLuFFdRcFQ No.]

Temporal mechanics don't work this way because the past is merely the past, not a finite place or straight path of causality but rather a past state of the current universe which doesn't exist, as the universe's current state alters with every imperceptible moment.

[Anonymous No.]

Hmmm. I think the key is in asking the gods "will [god x] answer 'no' to this question in your language"? Or something along those lines. Will have to work through the line of logic for given inputs of [god x].

[Anonymous No.]

>>2270608
I tried to read this post with this pic on mind.
I don't want to try again.

[Anonymous No.]

>>2270601
Actually, if Shirou dies, Archer still exists since he is removed from the flow of time, thus your paradox doesn't come to be.
The gamble is that even though they differentet entities, if 'EMIYA' kills 'EMIYA', the paradox will be great enough for the world to go 'Fuck this shit and unsolvable paradoxes' and erase him, thus putting an end to an afterlife of killing shit.
And of course, if it doesn't work, he will have killed a kid before destroying its life and take out his anger and regrets at this stupid young self.

[None !Nipaa0mi0. No.]

>>2270601
Did you just skip though all of UBW? Archer is a separate existence, so him killing Shirou won't actually accomplish anything. Even he realizes that, but he doesn't care as he just wants to have revenge on his younger self.

[Anonymous No.]

Don't worry. Before EMIYA can kill EMIYA a counter guardian will appear to stop it from happening.

[None !Nipaa0mi0. No.]

>>2270717
And then counter-guardian Emiya pops in to stop them.

[Anonymous No.]

Holy Grail can summon heroes from the future. Any future depending on the possible outcomes from the past. Archer would be the evil Shirou from the grimdark version of the future - in the alternate version of history where Shirou never even met his future self before.

[Anonymous No.]

>>2270723
Yo dawg, I heard you like EMIYA, so we made EMIYA fight EMIYA while EMIYA tries to stop EMIYA from killing EMIYA.

[Anonymous No.]

>>2270736
>>2270723

There are other counter guardians besides Archer.
For example, Shiki.
Shiki can kill servants afterall.

[White Ren !YLuFFdRcFQ No.]

>>2270777
Why does it turn out this way?

[Anonymous No.]

>>2270809
Because Shiki can kill servants can kill threads.

[Anonymous No.]

>>2270809
Didn't watch KnK5?

Araya basically said that Shiki is the counter guardian that the world set up to kill him.

[Anonymous No.]

>>2270847
Araya had too many blows to the forehead. Shiki was never appointed as a counter-guardian, he's just sore at how it happened.

[Anonymous No.]

What's so fun about all of Archer's drama is that he was in the throne of heroes even before he was born and pladged his soul to it.

[Anonymous of Russian Federation !6907282216 No.]

You're not going to make it with only "are you going to answer this question with the word that means no in your language,", you're going to have to ask "are you going to answer this question with the word that means YES in your language," as well.

[Anonymous of Russian Federation !6907282216 No.]

No, no, that's not the solution as well.

Worst case:
First: "are you going to answer this question with the word that means no in your language" - silence
Second: "are you going to answer this question with the word that means no in your language," - silence.

Now we have one liar confirmed and just one question to disguise from honest and random.

[Anonymous of Russian Federation !6907282216 No.]

Do gods know who the other two are? Can I ask something like ``Is the person I question first True?'' and expect reliable answer?

[Anonymous No.]

>>2271094

Yes, the gods know each other's identities.

Asking "Is B Random?" will get you a da or ja.

[Anonymous of Russian Federation !6907282216 No.]

Continue the sequence:
55
25
1215
11121115
31123115
132112132115

Problem 2: modify first number in Conway Sequence so that googling it won't give any results

[Anonymous of Russian Federation !6907282216 No.]

If you know identity of True, you may ask him: "Would you reply to question ``Is that person False?'' with the same word as to this question?" and then you know everybody. But there doesn't seem to be a way to reliably find someone's identity with two questions.

[Anonymous No.]

>>2271482
55
25
1215
11121115
31123115
132112132115

=> 11131221121113122115

[Anonymous of Russian Federation !6907282216 No.]

Oh, wait, no there is.

Okay, I have the solution.

This is a fucking awesome problem.

[None !Mystia3.V2 No.]

>>2271496
>11131221121113122115
311311222112311311222115

Oh, so you don't get numbers other than 1,2 and 3 even if you start with another number? Interesting.

[Anonymous of Russian Federation !6907282216 No.]

>>2271496
It's no fun if you know the answer already.

I spent two days thinking about it.

We were kind of doing it in group, with friends in university. So, the guy behind reads the sequence aloud: one. one one. two ones. one two one one. This is where it hit me. A real-life FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF moment. I felt so stupid for thinking about something this trivial for so long...