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>> No.35449435 [View]
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35449435

>>35449227
>>35449248
Additionally, because Yasu doesn't have to be listed as a name or included on the list of people killed, it is possible for her to act as those that are "dead" and still be alive. Therefore, we can further reduce the amount of people already on the island by utilizing Battlers own logic in Episode 3, whereby he claims that Jessica had another personality that killed Nanjo, and applying such that, there is an additional person who is faking, as there was already an individual faking death in the closed room chain, as two bodies no less. Then we can say that the individual sharing two bodies is not one of the 18 already mentioned on the island, and therefore their deaths are never confirmed in red. Additionally, because Kinzo is already dead, their inclusion wouldn't add more than 18 "individuals" on the island. With this logic, we can prove that Yasu was indeed able to exist on the island at the time of episode 3 and was the only one available to murder Nanjo. Additionally, with them being the unknown 4th person, it allows them to masquerade as the "dead". This explains how Shannon and Kanon are both brought back temporarily from the dead with magic. The human solution is that Yasu is both Kanon and Shannon and pretended to be both of those individuals in order to create the illusion that they were brought back from the dead. Additionally, they were the only ones without an alibi and alive at the time when Nanjo was murdered. Therefore, Nanjo was murdered by Yasu, who played the role of both Kanon, Shannon, and Beatrice, who were all personalities of Yasu, and whose death do not ever refer to the individual called Yasu. Therefore, Yasu must be Shannon and Kanon.

Also, note that Eva-BEATRICE does not deny the possibility that a personality could have "possessed" an individual with the red truth. She only denies that Jessica would be able to do it. Therefore the idea that multiple personalities can be counted is never denied in games 1-4, therefore Yasu being Kanon and Shannon is allowed and hinted at in these games, and is an acceptable solution to the mystery of these 4 games.

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