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/diy/ - Do-It-Yourself


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>> No.2047095 [View]
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My practice exam keeps giving design questions so I have 2 I want to ask about.
This one is a parallel-based limiter.
From the name, I can already tell that I'll be using a practical/conventional silicon diode with a turn-on voltage of 0.7v in parallel with the vout, however, because the vout on the positive end has a slope of less than 1, it means that I'll have a resistor on the same 'branch/line' on it as well as a resistor in series with it because I'll be using voltage divider in order to get the 1/3.
However, what I'm not sure about is the 2.5V and the -5V parts. I know how to get a slope of 1 within those points, as I can just turn off the diodes so that V_out would be the same as Vin if I have everything in parallel, but I'm not sure how to make the diodes even begin to have its clamping/clipping properties after -5V and it's normal 1/3 slope after 2.5V.
The reason for this is because the turn on voltage, 0.7v isn't a multiple of 2.5v, like I can make it have this 1/3 slope with 3 diodes conducting, meaning a 2.1V but idk how to make it 2.5, the same for -5V, with -4.9 (7 diodes)...

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