/diy/ - Do It Yourself

>>1861686
>Falstad is just using it's internal model to determine what is the current for that voltage, using the leakage current and emission coef.
I guess that's what I'm not understanding, because no matter how I play with the drop and resistors I'm not getting the numbers I think I should in the program.


1ohm resistor, 33.3v, 28 drop is giving me 2.9a across the led.

Which it should be well above that given the selection as far as I understand
1 = (33.3 - 28) / x
x = 5.3

I just don't understand how it's getting these numbers from what's set up